DE-BROGLIE WAVELENGTH

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I) In term of energy:-

      Kinetic energy of a potential of mass m moving with velocity v is given by
Where p is momentum of particles
Therefore,

We knowing that de- Broglie wavelength
               λ= h/p
Therefore,
 ........................(1)

II) In term of temperature:-

 From kinetic energy of gases, the average kinetic energy of a material particles at temperature T is given by

Where k is Boltzmann constant. The value of k= 1.38 x 10^-23 J/k
Putting this value in eq (1), we get
Therefore,
...................(2)

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